Optimal. Leaf size=177 \[ -\frac{3 i b c \text{PolyLog}\left (2,-e^{i \cos ^{-1}(c x)}\right )}{2 d^2}+\frac{3 i b c \text{PolyLog}\left (2,e^{i \cos ^{-1}(c x)}\right )}{2 d^2}+\frac{3 c^2 x \left (a+b \cos ^{-1}(c x)\right )}{2 d^2 \left (1-c^2 x^2\right )}-\frac{a+b \cos ^{-1}(c x)}{d^2 x \left (1-c^2 x^2\right )}+\frac{3 c \tanh ^{-1}\left (e^{i \cos ^{-1}(c x)}\right ) \left (a+b \cos ^{-1}(c x)\right )}{d^2}+\frac{b c}{2 d^2 \sqrt{1-c^2 x^2}}+\frac{b c \tanh ^{-1}\left (\sqrt{1-c^2 x^2}\right )}{d^2} \]
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Rubi [A] time = 0.181843, antiderivative size = 177, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 11, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.44, Rules used = {4702, 4656, 4658, 4183, 2279, 2391, 261, 266, 51, 63, 208} \[ -\frac{3 i b c \text{PolyLog}\left (2,-e^{i \cos ^{-1}(c x)}\right )}{2 d^2}+\frac{3 i b c \text{PolyLog}\left (2,e^{i \cos ^{-1}(c x)}\right )}{2 d^2}+\frac{3 c^2 x \left (a+b \cos ^{-1}(c x)\right )}{2 d^2 \left (1-c^2 x^2\right )}-\frac{a+b \cos ^{-1}(c x)}{d^2 x \left (1-c^2 x^2\right )}+\frac{3 c \tanh ^{-1}\left (e^{i \cos ^{-1}(c x)}\right ) \left (a+b \cos ^{-1}(c x)\right )}{d^2}+\frac{b c}{2 d^2 \sqrt{1-c^2 x^2}}+\frac{b c \tanh ^{-1}\left (\sqrt{1-c^2 x^2}\right )}{d^2} \]
Antiderivative was successfully verified.
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Rule 4702
Rule 4656
Rule 4658
Rule 4183
Rule 2279
Rule 2391
Rule 261
Rule 266
Rule 51
Rule 63
Rule 208
Rubi steps
\begin{align*} \int \frac{a+b \cos ^{-1}(c x)}{x^2 \left (d-c^2 d x^2\right )^2} \, dx &=-\frac{a+b \cos ^{-1}(c x)}{d^2 x \left (1-c^2 x^2\right )}+\left (3 c^2\right ) \int \frac{a+b \cos ^{-1}(c x)}{\left (d-c^2 d x^2\right )^2} \, dx-\frac{(b c) \int \frac{1}{x \left (1-c^2 x^2\right )^{3/2}} \, dx}{d^2}\\ &=-\frac{a+b \cos ^{-1}(c x)}{d^2 x \left (1-c^2 x^2\right )}+\frac{3 c^2 x \left (a+b \cos ^{-1}(c x)\right )}{2 d^2 \left (1-c^2 x^2\right )}-\frac{(b c) \operatorname{Subst}\left (\int \frac{1}{x \left (1-c^2 x\right )^{3/2}} \, dx,x,x^2\right )}{2 d^2}+\frac{\left (3 b c^3\right ) \int \frac{x}{\left (1-c^2 x^2\right )^{3/2}} \, dx}{2 d^2}+\frac{\left (3 c^2\right ) \int \frac{a+b \cos ^{-1}(c x)}{d-c^2 d x^2} \, dx}{2 d}\\ &=\frac{b c}{2 d^2 \sqrt{1-c^2 x^2}}-\frac{a+b \cos ^{-1}(c x)}{d^2 x \left (1-c^2 x^2\right )}+\frac{3 c^2 x \left (a+b \cos ^{-1}(c x)\right )}{2 d^2 \left (1-c^2 x^2\right )}-\frac{(3 c) \operatorname{Subst}\left (\int (a+b x) \csc (x) \, dx,x,\cos ^{-1}(c x)\right )}{2 d^2}-\frac{(b c) \operatorname{Subst}\left (\int \frac{1}{x \sqrt{1-c^2 x}} \, dx,x,x^2\right )}{2 d^2}\\ &=\frac{b c}{2 d^2 \sqrt{1-c^2 x^2}}-\frac{a+b \cos ^{-1}(c x)}{d^2 x \left (1-c^2 x^2\right )}+\frac{3 c^2 x \left (a+b \cos ^{-1}(c x)\right )}{2 d^2 \left (1-c^2 x^2\right )}+\frac{3 c \left (a+b \cos ^{-1}(c x)\right ) \tanh ^{-1}\left (e^{i \cos ^{-1}(c x)}\right )}{d^2}+\frac{b \operatorname{Subst}\left (\int \frac{1}{\frac{1}{c^2}-\frac{x^2}{c^2}} \, dx,x,\sqrt{1-c^2 x^2}\right )}{c d^2}+\frac{(3 b c) \operatorname{Subst}\left (\int \log \left (1-e^{i x}\right ) \, dx,x,\cos ^{-1}(c x)\right )}{2 d^2}-\frac{(3 b c) \operatorname{Subst}\left (\int \log \left (1+e^{i x}\right ) \, dx,x,\cos ^{-1}(c x)\right )}{2 d^2}\\ &=\frac{b c}{2 d^2 \sqrt{1-c^2 x^2}}-\frac{a+b \cos ^{-1}(c x)}{d^2 x \left (1-c^2 x^2\right )}+\frac{3 c^2 x \left (a+b \cos ^{-1}(c x)\right )}{2 d^2 \left (1-c^2 x^2\right )}+\frac{3 c \left (a+b \cos ^{-1}(c x)\right ) \tanh ^{-1}\left (e^{i \cos ^{-1}(c x)}\right )}{d^2}+\frac{b c \tanh ^{-1}\left (\sqrt{1-c^2 x^2}\right )}{d^2}-\frac{(3 i b c) \operatorname{Subst}\left (\int \frac{\log (1-x)}{x} \, dx,x,e^{i \cos ^{-1}(c x)}\right )}{2 d^2}+\frac{(3 i b c) \operatorname{Subst}\left (\int \frac{\log (1+x)}{x} \, dx,x,e^{i \cos ^{-1}(c x)}\right )}{2 d^2}\\ &=\frac{b c}{2 d^2 \sqrt{1-c^2 x^2}}-\frac{a+b \cos ^{-1}(c x)}{d^2 x \left (1-c^2 x^2\right )}+\frac{3 c^2 x \left (a+b \cos ^{-1}(c x)\right )}{2 d^2 \left (1-c^2 x^2\right )}+\frac{3 c \left (a+b \cos ^{-1}(c x)\right ) \tanh ^{-1}\left (e^{i \cos ^{-1}(c x)}\right )}{d^2}+\frac{b c \tanh ^{-1}\left (\sqrt{1-c^2 x^2}\right )}{d^2}-\frac{3 i b c \text{Li}_2\left (-e^{i \cos ^{-1}(c x)}\right )}{2 d^2}+\frac{3 i b c \text{Li}_2\left (e^{i \cos ^{-1}(c x)}\right )}{2 d^2}\\ \end{align*}
Mathematica [A] time = 0.464617, size = 251, normalized size = 1.42 \[ \frac{-6 i b c \text{PolyLog}\left (2,-e^{i \cos ^{-1}(c x)}\right )+6 i b c \text{PolyLog}\left (2,e^{i \cos ^{-1}(c x)}\right )-\frac{2 a c^2 x}{c^2 x^2-1}-3 a c \log (1-c x)+3 a c \log (c x+1)-\frac{4 a}{x}+\frac{b c \sqrt{1-c^2 x^2}}{1-c x}+\frac{b c \sqrt{1-c^2 x^2}}{c x+1}+4 b c \log \left (\sqrt{1-c^2 x^2}+1\right )-4 b c \log (x)+\frac{b c \cos ^{-1}(c x)}{1-c x}-\frac{b c \cos ^{-1}(c x)}{c x+1}-\frac{4 b \cos ^{-1}(c x)}{x}-6 b c \cos ^{-1}(c x) \log \left (1-e^{i \cos ^{-1}(c x)}\right )+6 b c \cos ^{-1}(c x) \log \left (1+e^{i \cos ^{-1}(c x)}\right )}{4 d^2} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.223, size = 260, normalized size = 1.5 \begin{align*} -{\frac{ca}{4\,{d}^{2} \left ( cx-1 \right ) }}-{\frac{3\,ca\ln \left ( cx-1 \right ) }{4\,{d}^{2}}}-{\frac{ca}{4\,{d}^{2} \left ( cx+1 \right ) }}+{\frac{3\,ca\ln \left ( cx+1 \right ) }{4\,{d}^{2}}}-{\frac{a}{{d}^{2}x}}-{\frac{3\,b\arccos \left ( cx \right ){c}^{2}x}{2\,{d}^{2} \left ({c}^{2}{x}^{2}-1 \right ) }}-{\frac{bc}{2\,{d}^{2} \left ({c}^{2}{x}^{2}-1 \right ) }\sqrt{-{c}^{2}{x}^{2}+1}}+{\frac{b\arccos \left ( cx \right ) }{{d}^{2}x \left ({c}^{2}{x}^{2}-1 \right ) }}-{\frac{2\,icb}{{d}^{2}}\arctan \left ( cx+i\sqrt{-{c}^{2}{x}^{2}+1} \right ) }-{\frac{{\frac{3\,i}{2}}cb}{{d}^{2}}{\it dilog} \left ( cx+i\sqrt{-{c}^{2}{x}^{2}+1} \right ) }-{\frac{{\frac{3\,i}{2}}cb}{{d}^{2}}{\it dilog} \left ( 1+cx+i\sqrt{-{c}^{2}{x}^{2}+1} \right ) }+{\frac{3\,bc\arccos \left ( cx \right ) }{2\,{d}^{2}}\ln \left ( 1+cx+i\sqrt{-{c}^{2}{x}^{2}+1} \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} -\frac{1}{4} \, a{\left (\frac{2 \,{\left (3 \, c^{2} x^{2} - 2\right )}}{c^{2} d^{2} x^{3} - d^{2} x} - \frac{3 \, c \log \left (c x + 1\right )}{d^{2}} + \frac{3 \, c \log \left (c x - 1\right )}{d^{2}}\right )} - \frac{{\left ({\left (6 \, c^{2} x^{2} - 3 \,{\left (c^{3} x^{3} - c x\right )} \log \left (c x + 1\right ) + 3 \,{\left (c^{3} x^{3} - c x\right )} \log \left (-c x + 1\right ) - 4\right )} \arctan \left (\sqrt{c x + 1} \sqrt{-c x + 1}, c x\right ) -{\left (c^{2} d^{2} x^{3} - d^{2} x\right )} \int \frac{{\left (6 \, c^{3} x^{2} - 3 \,{\left (c^{4} x^{3} - c^{2} x\right )} \log \left (c x + 1\right ) + 3 \,{\left (c^{4} x^{3} - c^{2} x\right )} \log \left (-c x + 1\right ) - 4 \, c\right )} \sqrt{c x + 1} \sqrt{-c x + 1}}{c^{4} d^{2} x^{5} - 2 \, c^{2} d^{2} x^{3} + d^{2} x}\,{d x}\right )} b}{4 \,{\left (c^{2} d^{2} x^{3} - d^{2} x\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{b \arccos \left (c x\right ) + a}{c^{4} d^{2} x^{6} - 2 \, c^{2} d^{2} x^{4} + d^{2} x^{2}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \frac{\int \frac{a}{c^{4} x^{6} - 2 c^{2} x^{4} + x^{2}}\, dx + \int \frac{b \operatorname{acos}{\left (c x \right )}}{c^{4} x^{6} - 2 c^{2} x^{4} + x^{2}}\, dx}{d^{2}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{b \arccos \left (c x\right ) + a}{{\left (c^{2} d x^{2} - d\right )}^{2} x^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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